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Thread Review (Newest First)
Posted by admin - 03-17-2026, 02:48 AM
"Firstly, we need to calculate the dimensional tension of the system. The tension in the fold depends on its thickness and how much strain it can take before breaking. In our case, that would be the difference between the volume of the inertial area and the volume of the folded space:

Tension=(Volumeinertial−Volumefold)/AreafoldTension = (Volume_{inertial} - Volume_{fold}) / Area_{fold}Tension=(Volumeinertial−Volumefold)/Areafold

"Next up is maintaining the energy baseline. The amount of energy required to hold a fold depends on its size, shape, and rigidity. In our case,

Energy=Foldvolume∗DensityEnergy = Fold_{volume} * DensityEnergy=Foldvolume∗Density

"With , this simplifies toBig Grinensity=1.5GJ/sqftDensity = 1.5 GJ/sqftDensity=1.5GJ/sqft

Energy=Volumefold∗1.5Energy = Volume_{fold} * 1.5Energy=Volumefold∗1.5

"Finally, regarding temporal divergence: if the amount of energy required to maintain the fold is more than what can be reasonably produced, then the system will become unstable and time dilation effects may occur. In our case:

TimeDilation=(Energyrequired−Energyproduced)/PowerdrawTime Dilation = (Energy_{required} - Energy_{produced}) / Power_{draw}TimeDilation=(Energyrequinewd−Energyproduced)/Powerdraw

"Apply these formulas to your case and see if it's feasible."